Answer:
[tex]q_{in} = 528.6\,\frac{kJ}{kg}[/tex]
Explanation:
Let assume that heating process occurs at constant pressure, the phenomenon is modelled by the use of the First Law of Thermodynamics:
[tex]q_{in} = h_{g} - h_{mix}[/tex]
The specific enthalpies are:
Liquid-Vapor Mixture:
[tex]h_{mix} = 2217.2\,\frac{kJ}{kg}[/tex]
Saturated Vapor:
[tex]h_{g} = 2745.8\,\frac{kJ}{kg}[/tex]
The thermal energy per unit mass required to heat the steam is:
[tex]q_{in} = 2745.8\,\frac{kJ}{kg} - 2217.2\,\frac{kJ}{kg}[/tex]
[tex]q_{in} = 528.6\,\frac{kJ}{kg}[/tex]
