answer
[tex]\frac{621}{2000}[/tex] ≈ 0.31 = 31 %
set up equation
the probability of someone from the first group having brown eyes is [tex]\frac{students-with-brown-eyes-in-first-group}{total-students-in-first-group }[/tex]
the probability of someone from the second group having brown eyes is [tex]\frac{students-with-brown-eyes-in-second-group}{total-students-in-second-group }[/tex]
so the probability of both students having brown eyes is[tex]\frac{students-with-brown-eyes-in-first-group}{total-students-in-first-group }[/tex]*[tex]\frac{students-with-brown-eyes-in-second-group}{total-students-in-second-group }[/tex]
values
students with brown eyes in first group = 27
total students in first group = 40
students with brown eyes in second group = 23
total students in second group = 50
plug in values and solve
[tex]\frac{students-with-brown-eyes-in-first-group}{total-students-in-first-group }[/tex]*[tex]\frac{students-with-brown-eyes-in-second-group}{total-students-in-second-group }[/tex]
= [tex]\frac{27}{40} *\frac{23}{50}[/tex]
= [tex]\frac{27 * 23}{40 * 50}[/tex]
= [tex]\frac{621}{2000}[/tex]
≈ 0.31
= 31 %
