Respuesta :
Answer:
Radial force component of force = 37.68 N
Explanation:
By Newton's 2 nd law of motion,
F = ma
F = 3.0 N, m = 0.5 Kg, a (Linear Acceleration ) = ?
3 = 0.5 a
a = 6 [tex]m/sec^{2}[/tex]
Now, a = 6 [tex]m/sec^{2}[/tex] , r = 2.5 m ,α(angular acceleration ) = ?
a = r α
6= 2.5 α
hence α = 2.4 rad/[tex]sec^{2}[/tex]
[tex]w= ?, w_0= 0, \alpha =2.4\ rad/sec^{2},\theta =2\ \pi (One\ Revolution)[/tex]
we know that,
[tex]w^{2} =w_0^2 +2 \alpha\cdot s\\ =0 + 2\cdot 2.4\cdot 2\pi\\=30.14 \\w=\sqrt{30.144} = 5.49\ Rad/ sec[/tex]
Radial force component of force = [tex]m r w^{2}[/tex]
since m =0.5 kg, r =2.5 m w =5.49 rad/sec
Radial force component of force =[tex]0.5\cdot\ 2.5\cdot\ 5.49^{2}[/tex] = 37.68 N
