Answer:
(A) [tex]HNO_{3}[/tex] Solubility will increase.
(B) [tex]NaOH[/tex] Solubility will decrease.
(C) [tex]Ca(NO_{3} )_{2}[/tex] Solubility will decrease.
Explanation:
a) According to Le Chatelier's Principle when a change is introduced in a reaction system at equilibrium, the system responds by the reaction shifting in the direction to counter the change introduced.
When the change introduced is addition of acid, some [tex]OH^{-}[/tex] are consumed due to it and the system would respond by reaction shifting towards creation of more [tex]OH^{-}[/tex] in the system by increased dissolution. Thus solubility increase.
(b) When [tex]OH^{-}[/tex] are added, the reaction shifts to counter the change introduced of increased [tex]OH^{-}[/tex] by shifting to side that decreases the increased [tex]OH^{-}[/tex]. That happens by reaction shifting towards some [tex]Ca (OH)_{2}[/tex] precipitating back. Hence solubility decreases.
(c) The change introduced is addition of [tex]Ca^{2+}[/tex] which will be countered by reaction shifting to side that decreases increased [tex]Ca ^{2+}[/tex], which happens by some [tex]Ca(OH)_{2}[/tex] precipitating back. Hence solubility decreases.