During summer weekdays, boats arrive at the inlet drawbridge according to Poisson distribution at a rate of 3 per hour. In a 2-hour period, what is the probability that no boats arrive

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Answer:

The probability that no boats arrive is [tex]2.48\times 10^{-3}[/tex].

Step-by-step explanation:

Poisson distribution:

Poisson distribution is a statistical distribution that helps to find out the probability of a certain is likely occur a specified period of time.

[tex]P(X=x)=\frac{e^{-\lambda t}(\lambda t)^x}{x!}[/tex]

[tex]\lambda[/tex] = rate.

Given that, Poisson distribution at a rate of 3 per hour.

[tex]\lambda[/tex] = 3

t=2

x=0

The probability that no boats arrive is

[tex]P(X=0)=\frac{e^{-2\times 3}(2\times 3)^0}{0!}[/tex]

                [tex]=2.48\times 10^{-3}[/tex]

The probability that no boats arrive will be [tex]2.48 \times 10^{-3}[/tex].

Given, boats arrive at the inlet drawbridge according to Poisson distribution at a rate of 3 per hour.

Now, we know that from poisson distribution, [tex]P (X=x) = \frac{e^{-Xt} (\lambda t)^x }{x!}[/tex]

Here, [tex]\lambda[/tex] [tex]=[/tex] rate

[tex]t = 2\\X = 0[/tex]

Now putting the above values in poissons equation we have,

[tex]P(X=0) = \frac{e^{-2\times3}(2\times3)^{0}}{0!} \\\\\\P = 2.48 \times 10^{-3}[/tex]

Hence the probability that no boats arrive will be [tex]2.48 \times 10^{-3}[/tex].

For more details on probability follow the link below:

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