Respuesta :
Answer:
126. g/mol is the molar mass of the acid .
Explanation:
[tex]HA+KOH\rightarrow KA+H_2O[/tex]
Moles of KOH = n
Volume of the solution of KOH = 19.0 mL = 0.019 L
Molarity of the KOH solution = 0.260 M
[tex]Molarity=\frac{Moles}{Volume(L)}[/tex]
[tex]0.260M=\frac{n}{0.019 L}[/tex]
[tex]n=0.260 M\times 0.019 L=0.00494 mol[/tex]
Accrding to recation, 1 mol KOH react with 1 mole of HA ,then 0.00494 mol of KOH will react with :
[tex]\frac{1}{1}\times 0.00494 mol=0.00494 mol[/tex] of HA
Mass of HA = 0.623 g
Molar mass of HA = M
[tex]0.00494 mol=\frac{0.623 g}{M}[/tex]
[tex[M=\frac{0.623 g}{0.00494 mol}=126. g/mol[/tex]
126. g/mol is the molar mass of the acid .
