If [tex]\int\limits^6_1[/tex] f(x)dx=22 and [tex]\int\limits^3_6[/tex] f(x)dx=10, what is the value of [tex]\int\limits^3_1[/tex] f(x)dx?

Answer:
32
Step-by-step explanation:
[1 , 6] = [1 , 3] + [3 , 6]
[6 , 3] = 10
[3 , 6] = -10
22 = [1 , 3] + (-10)
[1 , 3] = 22 + 10 = 32