If f(x)= [tex]\int\limits^x_0[/tex] cos(t^2)dt for -2.5≤x≤2.5, on which interval is f increasing?

Answer:
[-2.5, 2.17) U (-1.25, 1.25) U (2.17, 2.5]
Step-by-step explanation:
Function is increasing when
f'(x) > 0
f'(x) = cos(x²)
cos(x²) > 0
When x² is:
0《x² < pi/2
3pi/2 < x²《2.5²
0《x² < 1.570796327
-1.253314137 < x < 1.253314137
4.71238898 < x²《6.25
-2.5《x < 2.170803764
2.170803764 < x《2.5