Respuesta :
Answer:
Answer is option c
Step-by-step explanation:
[tex]given \: equations \: are \\ x - 2y = 15 \: \: and \: 2x + 4y = - 18 \\ divide \: by \: 2 \: in \: second \: equation \\ x + 2y = - 9 \: \: (equation \: 3) \\ adding \: 1and \: 3 \: we \: get \\ 2x = 6 \\ x = 3 \\ substitute \: x = 3 \: in \: equation \: 3 \\ 3 + 2y = - 9 \\ 2y = - 9 - 3 \\ 2y = - 12 \\ y = - 6[/tex]
x=3 and y=-6
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Answer:
x= 3 and y =-6
Step-by-step explanation:
I used elimination to solve it.
multiply the first equation by 2 so you can cancel out he y values
2 (x-2y=15)
2x- 4y = 30
2x +4y = -18 you can now eliminate -4y+4y because it makes
add the x's together 2x + 2x and do 30-18
4x=12 divide by 4
x =3
now that you know the value of x you use it to solve one of the original equations
3 -2y =15 subtract 3 from both sides
-2y = 15-3
-2y = 12 divide by -2
y = -6
