Answer:
7 .86×10^23 atoms of sulphur are contained in 41.8 g of sulphur
Explanation:
Molar mass of sulphur = 32 g/mol
Given mass of sulphur = 41.8g
Number of moles = Given mass / Molar Mass
So, number of moles of sulphur = 41.8/32 = 1.30625 moles
We know that,
In 1 mole of atom there are 6.022 × 10^23 number of atoms.
So, In 1.30625 moles of Sulphur arom, number of atoms = 1.30625 × 6.022 × 10^23 = 7.86×10^23 atoms
An atom is the smallest unit of ordinary matter that forms a chemical element.
There are [tex]7 .86*10^{23[/tex] atoms of sulphur are contained in 41.8 g of sulphur
The data is as given:-
The formula we will use is[tex]Number\ of\ moles = \frac{Given \ mass}{ Molar Mass}[/tex].
So, according to the formula the number of moles of sulphur = [tex]\frac{41.8}{32} = 1.30625 moles[/tex]
Therefore, In 1 mole of atoms, there is [tex]6.022 *10^{23[/tex] number of atoms.
So, In 1.30625 moles of Sulphur atom, number of atoms = [tex]1.30625 * 6.022 * 10^{23} = 7.86*10^{23} atoms[/tex]
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https://brainly.com/question/9899150
