Respuesta :

9514 1404 393

Answer:

  • a, a²
  • 1

Step-by-step explanation:

The form you're trying to match is ...

  (p +q)^2 = p^2 +2pq +q^2

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a) We can see that p = 4 and ...

  2pq = -8a

  2·4·q = -8a . . . . . use the known value of p

  q = -a . . . . . . . . . divide by 8

So, the identity is ...

  (4 -a)^2 = 16 -8a +a^2

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b) We see that p=3x, 2pq = -6x, and q^2 = 1. As above, we conclude ...

  2(3x)q = -6x

  q = -1 . . . . . consistent with q^2 = 1

The identity is ...

  (3x -1)^2 = 9x^2 -6x +1

Answer:

First one:

(4-a)^2=16-8a+a^2

Second:

(3x-1)^2=9x^2-6x+1