Answer:
The volume of the gas is 11, 2 L.
Explanation:
We use the ideal gas formula. We first convert the unit of temperature in degrees Celsius to Kelvin. We use the ideal gas constant R = 0.082 l atm / K mol. We solve v (volume) :
273K =0°C
PV=nRT ---> V= (nRT)/P
V= ( 3 mol x 0.082 l atm / K mol x 273 K) / 6 atm
V= 11, 193 L
