5 grams of water will have more water molecules since ice had 1.67 x [tex]10^{23}[/tex] molecules and 5 gm ice had 1.53 x 10[tex]10^{23}[/tex] molecules of water.
Explanation:
5 liters of water at 0 degrees or 273.15 K will have, Formula used is:
number of water molecules = [tex]\frac{mass}{atomic mass of 1 mole}[/tex] x Avagadro number
Avagadro number = 6.022 X 10 ^23 molecules or atoms in 1 mole
atomic mass of 1 mole water = 18.01 grams/mole
putting the value in the equation:
number of molecules = [tex]\frac{5}{18.01}[/tex] x 6.022 x 10^23
number of molecule of water in water = 1.67 X [tex]10^{23}[/tex] molecules.
5 gm cm^3 of ice will have
The density of ice = 0.917 gm/cm^3
volume = density x mass
number of moles of water = [tex]\frac{density x mass}{atomic mass of water}[/tex] x Avagadro number
putting the values,
number of moles in ice = [tex]\frac{0.917 X 5}{18.01}[/tex] X 6.022 X 10^23
= 1.53 X [tex]10^{23}[/tex] molecules of water
