S-t=3, s/3+t/2=6 solve it by using substitution method in linear equation

Answer:
s = 9, t = 6
Step-by-step explanation:
Given the 2 equations
s - t = 3 → (1)
[tex]\frac{s}{3}[/tex] + [tex]\frac{t}{2}[/tex] = 6 → (2)
Rearrange (1) expressing s in terms of t by adding t to both sides
s = 3 + t → (3)
Substitute s = 3 + t into (2)
[tex]\frac{3+t}{3}[/tex] + [tex]\frac{t}{2}[/tex] = 6
Multiply through by 6 to clear the fractions
2(3 + t) + 3t = 36 ← distribute and simplify left side
6 + 2t + 3t = 36
6 + 5t = 36 ( subtract 6 from both sides )
5t = 30 ( divide both sides by 5 )
t = 6
Substitute t = 6 into (3) for corresponding value of s
s = 3 + 6 = 9
Thus s = 9 and t = 6