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*WILL GIVE BRAINLIEST IF SOMEONE ANSWERS THIS CORRECTLY ASAP!!!!*

A substance exists in the solid, liquid, and gaseous states at three different temperatures. The temperatures and their corresponding states are shown in the table.

*Table Inserted Below*

Which of the following is the correct order of the relative strengths of the intermolecular forces in the three states?
A > B > C
A > C > B
B > C > A
C > B > A

WILL GIVE BRAINLIEST IF SOMEONE ANSWERS THIS CORRECTLY ASAP A substance exists in the solid liquid and gaseous states at three different temperatures The temper class=

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chivaslife529

Answer:

D. C > B >A

Hope it helps!

Explanation:

From strongest to weakest, the intermolecular forces rank in the following way:

Strongest: Hydrogen bonding. This occurs when compounds contain #"O"-"H"# , #"N"-"H"# , or #"F"-"H"# bonds. ...

Less strong: Dipole-dipole forces. ...

Weakest: London Dispersion Forces.

drpelezo

Answer:

The higher the temperature the weaker the intermolecular forces => B > C > A

Explanation:

Increasing temperature increases the internal kinetic energy the particles causing them to collectively move faster and further apart. The ability to move to positions of greater separation is a result of decreasing intermolecula forces.

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