Given:
Right triangle
θ = 60°
To find:
sin 60°
Solution:
The reference image is attached below.
The given triangle is a right triangle.
θ = 60°
Using basic trigonometric ratio formula:
[tex]$\sin \theta = \frac{\text{Opposite side to } \theta} {\text{Hypotenuse}}[/tex]
[tex]$\sin 60^\circ = \frac{\text{Opposite side to } 60^\circ} {\text{Hypotenuse}}[/tex]
[tex]$\sin 60^\circ = \frac{BC}{AC}[/tex]
The value of sin 60° = [tex]\frac{\sqrt{3} }{2}[/tex].
[tex]$\frac{\sqrt{3} }{2} = \frac{BC}{AC}[/tex]
In the given figure, the values of adjacent side, opposite side and hypotenuse are not given.
