Answer:
[tex]\frac{3}{28}[/tex]
Step-by-step explanation:
Probability (P) is calculated as
P = [tex]\frac{requiredoutcome}{count}[/tex]
The first required outcome is a red sweet from a total of 3 + 5 = 8
P( red) = [tex]\frac{3}{8}[/tex]
There are now 2 red left and a count of 7, since 1 has been eaten, thus
P( second red ) = [tex]\frac{2}{7}[/tex]
P( red and red ) = [tex]\frac{3}{8}[/tex] × [tex]\frac{2}{7}[/tex] = [tex]\frac{6}{56}[/tex] = [tex]\frac{3}{28}[/tex]
