Answer:
The length of the wire is 2.86 m
Explanation:
Given:
Current [tex]I = 0.76[/tex] A
Magnetic field [tex]B = 6 \times 10^{-5}[/tex] T
Force [tex]F = 9.4 \times 10^{-5}[/tex] N
Angle between wire and magnetic field [tex]\theta =[/tex] 46°
The magnetic force on the current carrying wire is given by,
[tex]F = BIl\sin \theta[/tex]
Where [tex]l =[/tex] length of wire
[tex]l = \frac{F}{BI \sin 46}[/tex]
[tex]l = \frac{9.4 \times 10^{-5} }{6 \times 10^{-5}\times 0.76 \times 0.7193}[/tex]
[tex]l = 2.86[/tex] m
Therefore, the length of the wire is 2.86 m
