Answer:
4.
Explanation:
Given,
frequency of standing wave = 603 Hz
length of string,L = 1.33 m
speed of the wave, v = 402 m/s
number of antinodes = ?
Wavelength of the standing wave
[tex]\lambda = \dfrac{v}{f}[/tex]
[tex]\lambda = \dfrac{402}{603}[/tex]
[tex]\lambda = 0.67\ m[/tex]
Number of anti nodes in the standing wave
[tex]n=\dfrac{l}{\frac{\lambda}{2}}[/tex]
[tex]n=\dfrac{2l}{\lambda}[/tex]
[tex]n=\dfrac{2\times 1.33}{0.67}[/tex]
n =3.97= 4.
Number of antinodes is equal to 4.
