Respuesta :
Answer:
[tex]p=<26,0,0> kg m/s[/tex]
Explanation:
Momentum is a vector quantity that represents the "amount of motion" of an object.
Mathematically, the momentum of an object is given by
[tex]p=mv[/tex]
where
m is the mass of the object
v is the velocity
Since momentum is a vector, it also has a direction, which is the same as the velocity.
Therefore, if we have two objects, the total momentum of the two objects will be obtained from the vector sum of the individual momenta of the two objects.
In this problem we have:
[tex]p_A= <20, -6, 0> kg m/s[/tex] is the momentum of object A
[tex]p_B =<6, 6, 0> kg m/s[/tex] is the momentum of object B
Therefore, the total momentum of objects A and B can be obtained by adding each components of A to the corresponding component of B, so:
[tex]p_x = 20 +6 = 26 kg m/s\\p_y = -6 +6 = 0 kg m/s\\p_z = 0 + 0 = 0 kg m/s[/tex]
So the total initial momentum is
[tex]p=<26,0,0> kg m/s[/tex]
The total initial momentum of this system, just before the collision is given by the equation p = < 26, 0, 0 > kg m/s.
Calculating the initial momentum:
Given information:
mass m[tex]_A[/tex] = 9 kg
mass m[tex]_B[/tex] = 13 kg
momentum of the respective masses is :
p[tex]_A[/tex] = < 20, -6, 0 > kg m/s
p[tex]_B[/tex] = < 6, 6, 0 > kg m/s
The <-,-,-> symbol represents the momentum in x , y , and z direction respectively. Each component will be added or subtracted according to its direction. Like x component will be added/subtracted from the x component of the other vector and the goes for y and z components.
So the total initial momentum of the system will be:
p = p[tex]_A[/tex] + p[tex]_B[/tex] = < 20, -6, 0 > kg m/s + < 6, 6, 0 > kg m/s
p = < 26, 0, 0 > kg m/s will be the initial momentum of the system before collision.
Learn more about momentum:
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