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A conducting loop of radius r=0.1 m, carrying a current I=2 A has a magnetic moment \vec{\mu} μ ​ that is entirely in the j-hat direction. The loop is immersed in a magnetic field \vec{B} B = [3 i-hat + 4 j-hat] T. What is the potential energy of the loop in this configuration?

Respuesta :

Answer:

Explanation:

Magnetic moment of current carrying loop

= current x area

= 2 x π x .1²

M  = .0628 unit . it is in j direction so vecor form of it

M = .0628 j

Magnetic field   B = 3i + 4 j

Energy

=  -  M.B

-  .0628 j . ( 3i + 4 j )

= - .2512 J

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