Answer:
The recoil speed of Astronaut A is 0.26 m/s.
Explanation:
Given that,
Mass of astronaut A, [tex]m_A=110\ kg[/tex]
Mass of astronaut B, [tex]m_B=74\ kg[/tex]
Astronaut A pushes B away, with B attaining a final speed of 0.4, [tex]v_B=0.4\ m/s[/tex]
We need to find the recoil speed of astronaut A. The momentum remains conserved here. Using the law of conservation of linear momentum as :
[tex]m_Av_A=m_Bv_B\\\\v_A=\dfrac{m_Bv_B}{m_A}\\\\v_A=\dfrac{74\times 0.4}{110}\\\\v_A=0.26\ m/s[/tex]
So, the recoil speed of Astronaut A is 0.26 m/s.