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A volleyball is spiked so that its incoming velocity of +2.06 m/s is changed to an outgoing velocity of -19.2 m/s. The mass of the volleyball is 0.350 kg. What is the magnitude of the impulse that the player applies to the ball? Number Units

Respuesta :

Answer:

J = 8.78 kgm/s

Explanation:

given  mass of volleyball = 0.350 kg

incoming velocity = +2.06 m/s = [tex]v_{1}[/tex]

outgoing velocity =-19.2 m/s =[tex]v_{2}[/tex]

we know impulse is change in momentum

so  impulse = J

[tex]J =mv_{1} -( m(-v_{2}))\\J = m(v_{1}+v_{2})\\J = 0.350( 2.06 + 19.2)\\ J = 0.350 \times 19.2\\ J = 8.78 kg m/s[/tex]

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