Answer:
[tex]sin \theta=\frac5{13}[/tex]
[tex]cos\theta=-\frac{12}{13}[/tex]
[tex]tan\theta =-\frac{5}{12}[/tex]
[tex]cec \theta=2\frac{3}{5}[/tex]
[tex]sec\theta=-1\frac1{12}[/tex]
[tex]cot \theta=-2\frac{2}{5}[/tex]
Step-by-step explanation:
Given point is (-24,10)
The distance between given point and the origin is
[tex]r=\sqrt{x^2+y^2}[/tex]
Here r [tex]=\sqrt{(-24)^2+(10)^2}[/tex]
=26 units.
x= -24 and y= 10
Now 6 trigonometric functions are
[tex]sin \theta=\frac yr=\frac{10}{26}=\frac5{13}[/tex]
[tex]cos\theta=\frac{x}{r}=\frac{-24}{26}=-\frac{12}{13}[/tex]
[tex]tan\theta =\frac{y}{x}=\frac{10}{-24}=-\frac{5}{12}[/tex]
[tex]cec \theta= \frac{r}{y}=\frac{26}{10}=\frac{13}{5}=2\frac{3}{5}[/tex]
[tex]sec\theta=\frac rx=\frac{26}{-24}=-\frac{13}{12}=-1\frac1{12}[/tex]
[tex]cot \theta=\frac{x}{y}=\frac{-24}{10}=-\frac{12}{5}=-2\frac{2}{5}[/tex]
