The daily profit P for a cake bakery can be modeled by the function P(x)= -15x^2 +330x -815. What should the price of a cake be to provide a daily profit of at least $600? Round answers to the nearest dollar.

Respuesta :

Answer:

[tex]5\leq \: x\leq 16[/tex]

Step-by-step explanation:

The daily profit P for a cake bakery is modeled by the function

[tex]P(x)= -15x^2 +330x -815.[/tex] where x=Price of Cakes Sold

We want to determine the value of x which will provide a daily profit of at least $600.

[tex]-15x^2 +330x -815\leq 600[/tex]

[tex]-15x^2 +330x -815-600\leq 0\\ -15x^2 +330x-1415\leq 0\\\text{Using Calculator to solve the quadratic equation}\\5.83\leq x \: or \: x\leq 16.16\\5\leq x\leq 16[/tex]

The minimum Price which the cakes can be sold is represented by the inequality

[tex]5\leq \: x\leq 16[/tex]