Answer: a) [tex]\dfrac{1}{15}[/tex] b) [tex]\dfrac{3}{5}[/tex]
Step-by-step explanation:
Since we have given that
Number of men = 4
Number of women = 2
So, number of selected people = 2
So, the probability that both officers are women would be
[tex]\dfrac{^2C_2}{^6C_2}\\\\=\dfrac{1}{15}[/tex]
And the probability that at least one of the two officers is a woman would be
[tex]\dfrac{^2C_1\times ^4C_1}{^6C_2}+\dfrac{^2C_2}{^6C_2}\\\\=\dfrac{2\times 4}{15}+\dfrac{1}{15}\\\\=\dfrac{8}{15}+\dfrac{1}{15}\\\\=\dfrac{8+1}{15}\\\\=\dfrac{9}{15}\\\\=\dfrac{3}{5}[/tex]
Hence, a) [tex]\dfrac{1}{15}[/tex] b) [tex]\dfrac{3}{5}[/tex]