Answer:
62979.09 s or 17.49 h
Explanation:
From the question,
The power from the solar needed to increase the temperature of water is given as,
P = P'A............. Equation 1
Where P = power, P' = intensity of sunlight, A = Area of the solar collector.
Given: P' = 550 W/m², A = 6.39 m².
Substitute into equation 1
P = 550(6.39)
P = 3514.5 W.
The amount heat required to change the temperature of water is given as,
Q = cm(t₂-t₁)........................... Equation 2
Where Q = amount of heat, c = specific heat capacity of water, m = mass of water, t₂ = Final temperature of water, t₁ = initial temperature of water
Given: c = 4200 J/kg.°C, m = Density×volume = 1000×1 = 1000 kg, t₂ = 72.1 °C, t₁ = 19.4 °C
Substitute into equation 2
Q = 4200(1000)(72.1-19.4)
Q = 4200(1000)(52.7)
Q = 221340000 J.
But,
P = Q/t
Where t = time.
Make t the subject of the equation,
t = Q/p............... Equation 3
t = 221340000/3514.5
t = 62979.09 s
t = (62979.09/3600) hrs
t = 17.49 h
