Answer:
The diameter to be used is 0.98 cm
Explanation:
The Poiseuille´s law is equal to:
[tex]Q=\frac{\pi Pr^{4} }{8\eta L}[/tex]
Where
Q = flow rate = 0.015 kg/min = 2.5x10⁻⁷m³/s
P = pressure difference = 25 Pa
r = radius
η = viscosity = 230 cP = 0.23 Pa s
L = length of the tube = 10 cm = 0.1 m
Clearing r:
[tex]r=\sqrt[4]{\frac{8\eta LQ}{\pi P} } =\sqrt[4]{\frac{8*0.23*0.1*2.5x10^{-7} }{\pi *25} } =0.0049m[/tex]
The diameter is:
[tex]d=2r=2*0.0049=0.0098m=0.98cm[/tex]