Answer:
102.5 grams of sodium phosphate will be needed.
Explanation:
[tex]Na_3PO_4(aq)\rightarrow 3Na^+(aq)+PO_4^{3-}(aq)[/tex]
Molarity of the sodium ions = [tex][Na^+]=1.00 M[/tex]
[tex]3\times[Na_3PO_4]= [Na^+][/tex]
[tex][Na_2PO_4]=\frac{1}{3}\times 1.00 M=1.00 M[/tex]
Mass of the sodium phosphate = m
Molar mass of sodium phosphate = 164 g/mol
Volume of the sodium phosphate solution = 625 mL = 0.625 L
1 mL = 0.001 L
Molarity of the sodium phosphate = [tex][Na_3PO_4]=1.00 M[/tex]
[tex]Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}[/tex]
[tex]1.00 M=\frac{m}{164 g/mol\times 0.625 L}[/tex]
m = 102.5 g
102.5 grams of sodium phosphate will be needed.
