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Write a program that queries information from three files. The first file (data1.txt) contains the names and telephone numbers of a group of people. The second file (data2.txt) contains the names and Social Security numbers of a group of people. The third file (data3.txt) contains the Social Security numbers and annual incomes of a group of people. The groups of people should overlap but need not be completely identical. Your program should ask the use for a telephone number and then print the name, Social Security number, and annual income, if it can determine that information.

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ohismike24

Answer:

file1=[ ]

file2=[ ]

file3=[ ]

f1=open('data1.txt','r')

for line in f1:

   line=line.strip().split(', ')

   file1.append((line[0],line[1]))

   f1.close()

f2=open('data2.txt','r')

for line in f2:

   line=line.strip().split(', ')

   file2.append((line[0],line[1]))

   f2.close()

f3=open('data3.txt','r')

for line in f3:

   line=line.strip().split(', ')

   file3.append((line[0],line[1]))

  f3.close()

l=[ ]

for x in file2:

   for y in file3:

       if x[1] in y:

           l.append((x[0],y))

final_file=[]

for x in file1:

   for y in l:

       if x[0] in y:

           final_file.append((x[1],y[0],*y[1]))

           

#This is where the program will ask the user for their telephone number

tel_num=input('Enter the telephone number: ')

temp=0

for data in final_file:

   if data[0]==tel_num:

       temp=1

       print('Telephone number: ',tel_num)

       print('Name: ',data[1])

       print('Social Security number: ',data[2])

       print('Annual income: ',data[3])

   

if temp==0:

   print('No data available for this telephone number.')

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