Answer:
Current in the loop is 0.063 A
Explanation:
Number of turns in the coil N = 150
Radius of the circular loop r = 7.5 cm = 0.075 m
So area [tex]A=\pi r^2=3.14\times 0.075^2=0.0176m^2[/tex]
Magnetic field B = 1.5 T
Maximum torque is given [tex]\tau =0.25Nm[/tex]
We have to find current in the coil
Torque on circular coil in magnetic field is equal to
[tex]\tau =BINA[/tex]
[tex]0.25=1.5\times I\times 150\times 0.0176[/tex]
I = 0.063 A
