Section BreakProblem 08.048 2.value: 5.00 pointsRequired information Problem 08.048.b Compute the expected error. The expected error is _____%. (Round the final answer to the nearest whole number.)

Respuesta :

Answer:

a) 19 or select the closest answer

b) 5%

Explanation:

a)

from the voltage divide rule

[tex]V_{in} = V_0 * \frac{R_2}{R_2 + R_f}[/tex]

[tex]\frac{V_0}{V_{in}} = \frac{R_2 + R_f}{R_2} => 1 + \frac{R_f}{R_2} = 20[/tex]

[tex]\frac{R_f}{R_2} = 19[/tex]

Select the nearest answer

b)

obtained gain = [tex]\frac{V_0}{V_{in}} = 1 + \frac{36}{2} = 19[/tex]

Expected gain = [tex]\frac{V_0}{V_{in}} = 20[/tex]

∴ error = |[tex]\frac{19 - 20}{20}[/tex]| × 100

            = 1/20 × 100            

            = 5%