Answer:
The value of the distance S = 62.5 m
Explanation:
From third law of motion
[tex]v^{2} = u^{2} + 2 as\\[/tex]
v = 0 & u = 30
So 0 = [tex]30^{2}[/tex] + 2 × a × 10
a = - 45 [tex]\frac{m}{s^{2} }[/tex]
When the car speed is 75 [tex]\frac{mi}{hr}[/tex] then in that case
u = 75 [tex]\frac{mi}{hr}[/tex] , v = 0
[tex]v^{2} = u^{2} + 2 as\\[/tex]
[tex]75^{2} = - 2 a S[/tex]
[tex]S = \frac{75^{2} }{-2 (-45)}[/tex]
S = 62.5 m
This is the value of the distance.
