Respuesta :
Answer: a) [tex][OH^-]=1.09\times 10^{-13}[/tex] and pH = 1.04
b) [tex][H^+]=1.02\times 10^{-11}[/tex] and [tex]pH=10.99[/tex]
c) [tex][H^+]=7.08\times 10^{-11}[/tex] and [tex][OH^-]=1.41\times 10^{-4}[/tex]
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration.
[tex]pH=-\log [H^+][/tex]
[tex]pOH=-\log [OH^-][/tex]
[tex]pH+pOH=14[/tex]
a) [tex][H^+]=0.090M[/tex]
[tex]pH=-\log [0.090]=1.04[/tex]
[tex]pOH=14-1.04=12.96[/tex]
[tex]12.96=-log[OH^-][/tex]
[tex][OH^-]=1.09\times 10^{-13}[/tex]
b) [tex][OH^-]=0.00098M[/tex]
[tex]pOH=-\log [0.00098]=3.01[/tex]
[tex]pH=14-3.01=10.99[/tex]
[tex]10.99=-log[H^+][/tex]
[tex][H^+]=1.02\times 10^{-11}[/tex]
c) [tex]pH=10.15[/tex]
[tex]10.15=-\log [H^+][/tex]
[tex][H^+]=7.08\times 10^{-11}[/tex]
[tex]pOH=14-10.15=3.85[/tex]
[tex]3.85=-log[OH^-][/tex]
[tex][OH^-]=1.41\times 10^{-4}[/tex]
