Answer:
368224.29906 m/s
Explanation:
M = Mass of Polonium nucleus = 214 u
V = Velocity of nucleus
m = Mass of Helium nucleus = 4 u
v = Velocity of alpha particle = [tex]1.97\times 10^7\ m/s[/tex]
In this system the momentum is conserved
[tex]MV+mv=0\\\Rightarrow MV=-mv\\\Rightarrow 214V=-4\times 1.97\times 10^7\\\Rightarrow V=\dfrac{-4\times 1.97\times 10^7}{214}\\\Rightarrow V=368224.29906\ m/s[/tex]
The recoil speed of the nucleus that remains after the decay is 368224.29906 m/s
