Respuesta :
Answer:
0.569 m.
Explanation:
Given,
Speed of electron, v = 5 x 10⁶ m/s
Assuming earth magnetic field be equal to B = 5 x 10⁻⁵ T
radius of the circular orbit, r = ?
Equating centrifugal force to magnetic force
[tex]\dfrac{mv^2}{r}=qvB[/tex]
[tex]r = \dfrac{mv}{qB}[/tex]
q is the charge of electron
m is mass of electron
[tex]r = \dfrac{9.11\times 10^{-31}\times 5\times 10^{-6}}{1.6\times 10^{-19}\times 5\times 10^{-5}}[/tex]
[tex]r = 0.569\ m[/tex]
radius of circular orbit is equal to 0.569 m.
The radius of the circular orbit is 0.569 m.
Calculation of the radius of the circular orbit:
Since
Speed of electron, v = 5 x 10⁶ m/s
Assuming earth magnetic field be equal to B = 5 x 10⁻⁵ T
So, here we have to equate centrifugal force to magnetic force
So,
mv^2/r = qvB
So,
r = mv/qB
here
q is the charge of the electron
m is the mass of electron
So,
r = 9.11*10^-31*5*10^-6/1.6*10^-19*5*10^-5
= 0.569 m
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