The motor exerts a force of F = (20t2) N on the cable, where t is in seconds. Determine the speed of the 25-kg crate when t = 4 s. The coefficients of static and kinetic friction between the crate and the plane are ms = 0.3 and mk = 0.25, respectively.

Respuesta :

Answer:

Explanation:

Force F = 20 t² N so force is variable.

friction on the crate = mgμ , μ is coefficient of kinetic  friction , m is mass

Net force

=  F - mgμ

= 20 t² - mgμ = m dv / dt  ( Newton's 2 nd law )

m dv = (20 t² - mgμ ) dt

Integrating on both sides,

m v  = 20 (t³ / 3) - mgμ t

Putting the values ,

25 x v = 20 x 4³/3 - 25 x 9.8 x .25 x 4

25 v = 426.67 - 245

25 v = 181.67

v = 7.27

v = 7.27  m /s

The study of matter is called physic.

The correct answer is 7.27.

Force F = 20 t² N so the force is variable.

The friction on the crate is mgμ

  • μ is coefficient of kinetic friction,
  • m is mass
  • g is the gravitational force

The solution to the question is:-

=  F - mgμ

= 20 t² - mgμ

= [tex]m\frac{dv}{dt}[/tex]

m dv = (20 t² - mgμ ) dt

m v  = 20 (t³ / 3) - mgμ t

After Putting the values, we will get:-

[tex]25 * v = 20 * \frac{4^3}{3} - 25 * 9.8 * .25 * 4[/tex]

[tex]25 v = 426.67 - 24525 v = 181.67v = 7.27[/tex]

Hence, the correct answer is v = 7.27  m /s.

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https://brainly.com/question/20293447