Answer:
Rate of change of magnetic field is [tex]3.466\times 10^3T/sec[/tex]
Explanation:
We have given diameter of the circular loop is 13 cm = 0.13 m
So radius of the circular loop [tex]r=\frac{0.13}{2}=0.065m[/tex]
Length of the circular loop [tex]L=2\pi r=2\times 3.14\times 0.065=0.4082m[/tex]
Wire is made up of diameter of 2.6 mm
So radius [tex]r=\frac{2.6}{2}=1.3mm=0.0013m[/tex]
Cross sectional area of wire [tex]A=\pi r^2=3.14\times0.0013^2=5.30\times 10^{-6}m^2[/tex]
Resistivity of wire [tex]\rho =2.18\times 10^{-8}m[/tex]
Resistance of wire [tex]R=\frac{\rho L}{A}=\frac{2.18\times 10^{-8}\times 0.4082}{5.30\times 10^{-6}}=1.67\times 10^{-3}ohm[/tex]
Current is given i = 11 A
So emf [tex]e=11\times 1.67\times 10^{-3}=0.0183volt[/tex]
Emf induced in the coil is [tex]e=-\frac{d\Phi }{dt}=-A\frac{dB}{dt}[/tex]
[tex]0.0183=5.30\times 10^{-6}\times \frac{dB}{dt}[/tex]
[tex]\frac{dB}{dt}=3.466\times 10^3=T/sec[/tex]
