Answer:
See attachment
Step-by-step explanation:
English:
We make a table of values for the function:
[tex]f(x) = 2 {x}^{2} - 3x + 1[/tex]
Solution
To make a table of values for this function, we substitute some x-values and calculate the corresponding y-values.
Let choose x=-2 to 2.
When x=-2 ,
[tex]f( - 2) = 2 {( - 2)}^{2} - 3( - 2) + 1[/tex]
[tex]f( - 2) = 2(4) + 3( 2) + 1 = 15[/tex]
When x=-1,
[tex]f( - 1) = 2 {( - 1)}^{2} - 3( - 1) + 1 = 6[/tex]
When x=0,
[tex]f( 0) = 2 {( 0)}^{2} - 3( 0) + 1 = 1[/tex]
When x=1,
[tex]f( 1) = 2 {( 1)}^{2} - 3( 1) + 1 = 0[/tex]
When x=2,
[tex]f( 2) = 2 {( 2)}^{2} - 3( 2) + 1 = 3[/tex]
The table is shown in attachment
