contestada

A 13-N weight and a 12-N weight are connected by a massless string over a massless, frictionless pulley. The 13-N weight has a downward acceleration with magnitude equal to that of a freely falling body times:
A. 1
B. 1/12
C. 1/13
D. 1/25
E. 13/25

Respuesta :

lublana

Answer:

D

Explanation:

We are given that

Weight,[tex]w_1=13 N[/tex]

[tex]w_2=12 N[/tex]

We have to find the acceleration of 13 N weight .

[tex]m_1=\frac{w_1}{g}=\frac{13}{g}[/tex]kg

[tex]m_2=\frac{w_2}{g}=\frac{12}{g} kg[/tex]

Net force,[tex]w_1-w_2=13-12=1 N[/tex]

Total mass,[tex]m=m_1+m_2=\frac{13}{g}+\frac{12}{g}=\frac{25}{g}[/tex]kg

Acceleration,[tex]a=\frac{Net\;force}{total\;mass}[/tex]

Using the formula

[tex]a=\frac{1}{\frac{25}{g}}=\frac{1}{25}g[/tex]

Where g=Acceleration due to gravity

Hence, option D is true.

Otras preguntas