Respuesta :
Answer:
There were 7 cats
Step-by-step explanation:
In this question, we are asked to calculate the number of individual cats and dogs present at an animal shelter on a certain Monday.
Since we do not know the exact numbers, let’s represent these animals by variables. Let the number of dogs be d and the number of cats be c .
Since there are a total of 9 animals, this means;
c + d = 9 •••••••••(I)
Let’s now get the second equation out of their finances;
Total amount spent on dogs will be 7 * d = 7d while total amount spent on cats will be 5.5 * c = 5.5c. If we add both, we will get the total amount spent which is $52.5
Mathematically therefore;
5.5c + 7d = 52.5 ••••••••(ii)
Now from 1, we can say that c = 9 - d
Let’s substitute this in ii
5.5(9-d) + 7d = 52.5
49.5 - 5.5d + 7d = 52.5
1.5d = 52.5 - 49.5
1.5d = 3
d = 3/1.5 = 2
Since d = 2, c = 9 - d = 9 - 2 = 7
Answer: There were 7 cats at the shelter on Monday.
Step-by-step explanation:
Hi, to answer this question we have to write a system of equations using the information given.
- c + d = 9 (there were a total of 9 cats (c) and dogs (d) on Monday)
- 5.50 c + 7 d = 52.50 (An animal shelter spends $5.50 per day to care for each cat and $7.00 per day to care for each dog)
Isolating d on the first equation:
d =9 -c
Replacing the value of d in the second equation
5.50 c + 7 d = 52.50
5.50 c + 7 (9-c) = 52.50
5.50c +7(9) -7(c) =52.50
5.50c +63 -7c =52.50
63 -52.50 = 7c-5.50c
10.5= 1.5c
10.5/1.5=c
c= 7
There were 7 cats at the shelter on Monday.
Feel free to ask for more if needed or if you did not understand something.
