Answer:
The angular separation between the red and violet components of the spectrum that emerges from the glass is 1.72°
Explanation:
Given:
Refractive index for red light [tex]n _{1} = 1.620[/tex]
Refractive index for violet [tex]n' _{1} = 1.660[/tex]
Refractive index for air [tex]n_{2} = 1[/tex]
Incident angle [tex]\theta _{1} =[/tex] 28.30°
According to the snell's law,
[tex]n_{1} \sin \theta _{1} = n_{2} \sin \theta _{2}[/tex]
For red light,
[tex]1.620 \times \sin 28.30 = 1 \sin \theta _{2}[/tex]
Where [tex]\theta _{2} =[/tex] transmitted angle for red light
[tex]\theta _{2} =[/tex] 50.18°
For violet light,
[tex]1.660 \times \sin 28.30 = 1 \sin \theta' _{2}[/tex]
Where [tex]\theta' _{2} =[/tex] transmitted angle for violet light
[tex]\theta' _{2} =[/tex] 51.9°
Angular separation between red and violet light is given by,
[tex]\theta ' _{2} - \theta _{2} = 51.9 -50.18 =[/tex] 1.72°
Therefore, the angular separation between the red and violet components of the spectrum that emerges from the glass is 1.72°