Answer:
1587.2 g
Explanation:
First of all, we need to calculate the number of moles of oxygen. We can do it by using the equation of state for an ideal gas:
[tex]pV=nRT[/tex]
where in this case:
[tex]p=1.9 atm[/tex] is the pressure of the gas
V = 640 L is the volume
n is the number of moles
[tex]R=0.082 atm L mol^{-1} K^{-1}[/tex] is the gas constant
[tex]T=26^{\circ}C+273=299 K[/tex] is the absolute temperature of the gas
Solving for n, we find:
[tex]n=\frac{pV}{RT}=\frac{(1.9)(640)}{(0.082)(299)}=49.6 mol[/tex]
Now we can find the mass of the oxygen by using the formula:
[tex]m=nM[/tex]
where:
n = 49.6 mol is the number of moles
M = 32 g/mol is the molar mass of molecular oxygen
Therefore, substituting,
[tex]m=(49.6)(32)=1587.2 g[/tex]
