Answer:
Minimum radius of the curve to stay on the road will be equal to [tex]0.255v^2m[/tex]
Explanation:
We have given coefficient of kinetic friction [tex]\mu =0.40[/tex]
Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]
We have to find minimum radius of the curve so that car will stay on the road
For the car to stay on the road centripetal force must be equal to frictional force
So [tex]\frac{mv^2}{r}=\mu mg[/tex]
So minimum radius of the
[tex]r=\frac{v^2}{\mu g}=\frac{v^2}{0.4\times 9.8}=0.255v^2m[/tex]
So minimum radius of the curve to stay on the road will be equal to [tex]0.255v^2m[/tex]
