Answer:
0.82 m
Explanation:
We are given that
Weight,[tex]w_1[/tex]=225 N
Length,l=5 m
d=1.1 m
We have to find the distance x for which person weighs 385 N walk on the overhanging part of the plank before it just begins to tip.
Half length=[tex]\frac{l}{2}=\frac{5}{2}=2.5 m[/tex]
[tex]r=\frac{l}{2}-d=2.5-1.1=1.4 m[/tex]
[tex]w_2=385 N[/tex]
When system in equilibrium then
[tex]w_1r=w_2 x[/tex]
[tex]225\times 1.4=385\times x[/tex]
[tex]x=\frac{225\times 1.4}{385}[/tex]
[tex]x=0.82 m[/tex]