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A sample of argon gas, Ar(g). is placed in a 3.80 L container at 320 K. The gas pressure is 0.496 atm.
How many moles of Ar gas are in the container?

Respuesta :

Neetoo

Answer:

n = 0.072 mol

Explanation:

Given data:

Volume of gas = 3.80 L

Temperature of gas = 320 K

Pressure of gas = 0.496 atm

Number of moles of Ar gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will put the values.

n = PV/RT

n = 0.496 atm ×3.80 L / 0.0821 atm.L/ mol.K ×  320 K

n = 1.88 /26.27 /mol

n = 0.072 mol

Moles of Ar gas in the container is 0.072 mol.

Given:-

Volume of gas = 3.80 L

Temperature of gas = 320 K

Pressure of gas = 0.496 atm

Number of moles of Ar gas = ?

Ideal gas equation:-

[tex]PV=nRT[/tex].......(1)

Here, P= Pressure, V = volume, and n = number of moles

R = gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Substitute all the values in equation (1) as follows:-

[tex]n = 0.496 atm\times3.80 L / 0.0821 atm.L/ mol.K\times320 K\\\\n = 1.88 /26.27 \ mol\\\\n\ = 0.072\ mol[/tex]

So, the moles of Ar gas in the container are 0.072 moles.

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