destwitchy
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h(t)=(t+3)
2
+5h, left parenthesis, t, right parenthesis, equals, left parenthesis, t, plus, 3, right parenthesis, squared, plus, 5
What is the average rate of change of hhh over the interval -5\leq t\leq -1−5≤t≤−1minus, 5, is less than or equal to, t, is less than or equal to, minus, 1?

Respuesta :

MathPhys

Answer:

0

Step-by-step explanation:

h(t) = (t + 3)² + 5, -5 ≤ t ≤ -1

The average rate of change is the change in h over the change in t.

(h(-1) − h(-5)) / (-1 − (-5))

= ((-1 + 3)² + 5 − ((-5 + 3)² + 5)) / (-1 + 5)

= (4 + 5 − 4 − 5)) / 4

= 0

kapoorprachi783

The answer is 0. To understand the question check below.

What is the average rate of change?

It is a measure of how much the function changed per unit, on average, over that interval.

Given,

⇒ h(t) = (t + 3)² + 5, -5 ≤ t ≤ -1

The average rate of change is the change in h over the change in t.

⇒ (h(-1) − h(-5)) / (-1 − (-5))

⇒ ((-1 + 3)² + 5 − ((-5 + 3)² + 5)) / (-1 + 5)

⇒ (4 + 5 − 4 − 5)) / 4

⇒ 0

The average rate of change is the change in one quantity with respect to the change in another. It is a measure of how much the function changed per unit in a particular interval.

Learn more about average rate of change here: brainly.com/question/8728504

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