Respuesta :
Answer:
percentage yield = 48. 82%
Explanation:
Firstly, the chemical equation of the reaction is written and balanced.
P4(g) + O2(g) → P4O6
balanced equation.
P4(s) + 3 O2(g) → P4O6(s)
We have to know the limiting reactant of the reaction by converting the reactants to mole
molar mass of phosphorus = 4 × 31 = 124 g
moles of phosphorus = mass/molar mass = 75.3/124 = 0.60725806451 mol-rxn
molar mass of oxygen = 32 g
moles of oxygen = 38.7/ 32 = 1.209375 / 3 mol = 0.403125 mol-rxn
Therefore the limiting reactant is oxygen and it will determine the amount of product
P4(s) + 3 O2(g) → P4O6(s)
mass of 3 moles of oxygen = 3 × 32 = 96 g
molar mass of P4O6 = 124 + 96 = 220 g
if 96 g of oxygen produces 220 g of P4O6
38.7 g of oxygen will produce ? grams of P4O6
theoretical yield of P4O6 = (38.7 × 220)/96
theoretical yield of P4O6 = 8514 /96
theoretical yield of P4O6 = 88.6875
theoretical yield of P4O6 = 88.69
percentage yield = actual yield/theoretical yield × 100
percentage yield = 43.3/88.69 × 100
percentage yield = 4330/88.69
percentage yield = 48.8217386402
percentage yield = 48. 82%
Answer:
The percent yield of the reaction is 48.9 %
Explanation:
Step 1: data given
Mass of phosphorus = 75.3 grams
Molar mass of phosphorus = 123.90 g/mol
Mass of oxygen = 38.7 grams
Molar mass oxygen = 32.0 g/mol
Mass of P4O6 produced = 43.3 grams
Step 2: The balanced equation
P4(s) + 3O2(g) → P4O6(s)
Step 3: Calculate moles P4
Moles P4 = mass P4 / molar mass P4
Moles P4 = 75.3 grams / 123.90 g/mol
Moles P4 = 0.608 moles
Step 4: calculate moles O2
Moles O2 = 38.7 grams / 32.0 g/mol
Moles O2 = 1.21 moles
Step 5: Calculate the limiting reactant
For 1 mol P4 we need 3 moles O2 to produce 1 mol P4O6
O2 is the limiting reactant. There will react 1.21 moles. P4 is in excess. There will react 1.21 / 3 = 0.403 moles. There will remain 0.608 - 0.403 = 0.205 moles P4
Step 6: Calculate moles P4O6
For 1 mol P4 we need 3 moles O2 to produce 1 mol P4O6
For 1.21 moles O2 we'll have 1.21 / 3 = 0.403 moles P4O6
Step 7: Calculate mass P4O6
Mass P4O6 = moles P4O6 * molar mass P4O6
Mass P4O6 = 0.403 moles * 219.88 g/mol
Mass P4O6 = 88.6 grams
Step 8: Calculate percent yield
% yield = (actual yield / theoretical yield) * 100%
% yield = (43.3 grams / 88.6 grams ) *100 %
% yield = 48.9 %
The percent yield of the reaction is 48.9 %
