Answer:
95% Confidence interval: (0.8907,0.9293)
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 846
Proportion of respondents who said the internet has been a good thing for them personally = 91%
[tex]\hat{p} = 0.91[/tex]
95% Confidence interval:
[tex]\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex]
[tex]z_{critical}\text{ at}~\alpha_{0.05} = 1.96[/tex]
Putting the values, we get:
[tex]0.91\pm 1.96(\sqrt{\dfrac{0.91(1-0.91)}{846}})\\\\ = 0.91\pm 0.0193\\\\=(0.8907,0.9293)[/tex]
(0.8907,0.9293) is the required 95% confidence interval for the proportion of respondents who say the internet has been a good thing for them personally.