Answer:
Concentration of Si in kilograms = 19.55 kg/m³
Explanation:
given data
concentration of Si = 0.25 %
Densities of Si = 2.33 g/cm³ × [tex]10^6[/tex] g/m³
Densities of Fe = 7.87 g/cm³ × [tex]10^6[/tex] g/m³
solution
we know that Weight of Si is = 0.25 g or 0.00025 kg
so here Weight of Fe will be
Weight of Fe = 100 - 0.25
Weight of Fe = 99.75 g or 0.09975 kg
and we know
volume = [tex]\frac{Wight}{density}[/tex]
and
Concentration of Si in kilograms is express as
Concentration of Si in kilograms = [tex]\frac{\text{Weight of Si in 100 g of alloy}}{\text{Volume of 100 g of alloy}}[/tex] ................1
put here value and we get
Concentration of Si in kilograms = [tex]\frac{0.00025}{\frac{99.75}{7.87\times 10^6}+\frac{0.25}{2.23\times 10^6}}[/tex]
Concentration of Si in kilograms = 19.55 kg/m³